Posted by Steve on Saturday, April 14, 2012 at 4:36pm.
First, calculate Q
(HI)^2/(H2)(I2) = (0.05)^2/(O>1)^2 = 0.25 which is too small; therefore the reaction will move to the right.
..........H2 + I2 ==> 2HI
initial..0.1...0.1....0.05
change..-x....-x.....+x
equil....0.1-x..0.1-x...0.05+x
Set up Kc = (HI)^2/(H2)(I2)
Solve for x, 0.1-x and 0.05+x
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