waves propagate down a 25gram string at 35 m/s. If the string has a length 1.5 meters, what iss the magnitude of the tension acting along it? i am stuck on how to figure this one out any help would be appriciated.

Mass per unit length

m(o) = m/L = 0.025/1.5 = 0.0166 kg/m
Velocity in the stretched string is
v = sqrt(T/m(o)).
T = m(o)•v^2 = 0.0166•(35)^2=20.34 N

Thank you

A hydraulic lift of the type shown below is used to raise a car weighing 15,000 N. The piston that supports the car has a diameter of 36 cm. What pressure of air within the system is required to just hold the car in place?

To determine the magnitude of the tension acting along the string, we can use the equation for wave velocity:

v = √(T/μ)

where:
v is the wave velocity (given as 35 m/s),
T is the tension in the string, and
μ is the linear mass density of the string.

The linear mass density, μ, is calculated by dividing the mass of the string by its length:

μ = m/L

where:
m is the mass of the string (given as 25 grams, but should be converted to kilograms) and
L is the length of the string (given as 1.5 meters).

Let's calculate the linear mass density first:
Convert the mass of the string to kilograms:
m = 25 grams = 0.025 kg
Now, we can calculate the linear mass density:
μ = m / L
μ = 0.025 kg / 1.5 m
μ ≈ 0.0167 kg/m

Now that we have the linear mass density, we can rearrange the wave velocity equation to solve for T:

T = (v^2) * μ

Substitute the known values:
T = (35 m/s)^2 * 0.0167 kg/m
T ≈ 20.18 N

Therefore, the magnitude of the tension acting along the 1.5-meter string is approximately 20.18 Newtons.