Post a New Question

posted by m Saturday, April 14, 2012 at 5:25am.

Just as a car tops a 51 meter high hill with a speed of 85 km/h it runs out of gas and coasts from there, without friction or drag. How high, to the nearest meter, will the car coast up the next hill?

v =85 km/h= 23.61 m/s. mv^2/2+mgh = mgH. H = h +v^2/2g =51 +28.44 =79.44 m.

"solutio"n v=85km/h v=85*1000/60*60 v=85000/3600 v=23.61m/s H=h+v*v/2g =51+23.61*23.61/2*9.8 =51+557.4/19.6 =51+28.44 H=79.44m.

More Related Questions