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December 19, 2014

December 19, 2014

Posted by **Anonymous** on Saturday, April 14, 2012 at 4:39am.

- Math -
**Steve**, Saturday, April 14, 2012 at 5:00amlet u = x^2

we have

f = 1/2∫e^-u du

f(x) = -1/2 e^(-x^2) + C

1 = -1/2 (1) + C

C = 3/2

f(x) = -1/2 e^(-x^2) + 3/2

f(1) = -1/2 * 1/e + 3/2

= 1/2 (3 - 1/e)

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