Posted by Briana on Friday, April 13, 2012 at 3:17pm.
sin (30/2) = +/- sqrt [(1-cos 30)/2]
+ in first quadrant
= sqrt [ (1 - {sqrt 3}/2)/2) ]
= sqrt [ (2 - sqrt 3)/4 ]
= (1/2) sqrt (2 - sqrt 3)
use
cos 2A = 1 - 2sin^2 A
cos 30° = 1 - 2sin^2 15°
√3/2 = 1- 2sin^2 15°
2sin^2 15° - 1 - √3/2 = (2-√3)/2
sin^2 15° = (2-√3)/4
sin 15° = √(2-√3) /2
it would have been easier to do
sin15°
= sin(45°-30°)
= sin45cos30 - cos45sin30
= (√2/2)(√3/2) -(√2/2)(1/2)
= (√6 - √2)/4 which yields the same result as above
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