Posted by **Mary** on Friday, April 13, 2012 at 12:04pm.

Please explain to work this:

A rocket is launched from atop a 105-foot cliff with an initial velocity of 156ft/s. the height of the rocket above the ground at time t is given by

h= -16t^2 + 156t + 105. When will the

rocket hit the ground after it is launched? Round to the nearest second.

- math -
**Steve**, Friday, April 13, 2012 at 12:20pm
naturally, when h = 0.

-16t^2 + 156t + 105 = 0

t = (39 ± √1941)/8

t = 10 sec

- math -
**Nix The Robot**, Friday, April 13, 2012 at 4:40pm
???????????????????????????????????????Your confusing me! STOP CONFUSING ME!!!!!

## Answer this Question

## Related Questions

- physics - a rocket is launched from atop a 105-foot cliff with an initial ...
- AlgebraB-2 - 1. What is the value of n so that the expression x² + 12x + n is a ...
- AlgebraB-2 - I need help with figuring out how to do these problems to get the ...
- AlgebraB-2 - Thanks everybody, I got a solution for figuring out the answer (...
- math - A rocket is launch from the top of an 40 foot cliff with an initial ...
- Algebra: Quadratic Functions - A model rocket is launched with an initial ...
- Math/calculus - a toy rocket is shot into the air at the top of a building so ...
- physics - A stationary rocket is launched vertically upward. After 4s, the ...
- Algebra: Quadratic Functions - if a rocket is launched straight up into the air ...
- math - A model rocket is launched with an initial velocity of 160 ft/s. The ...

More Related Questions