Thursday

October 23, 2014

October 23, 2014

Posted by **Mary** on Friday, April 13, 2012 at 12:04pm.

A rocket is launched from atop a 105-foot cliff with an initial velocity of 156ft/s. the height of the rocket above the ground at time t is given by

h= -16t^2 + 156t + 105. When will the

rocket hit the ground after it is launched? Round to the nearest second.

- math -
**Steve**, Friday, April 13, 2012 at 12:20pmnaturally, when h = 0.

-16t^2 + 156t + 105 = 0

t = (39 ± √1941)/8

t = 10 sec

- math -
**Nix The Robot**, Friday, April 13, 2012 at 4:40pm???????????????????????????????????????Your confusing me! STOP CONFUSING ME!!!!!

**Answer this Question**

**Related Questions**

physics - a rocket is launched from atop a 105-foot cliff with an initial ...

AlgebraB-2 - 1. What is the value of n so that the expression x² + 12x + n is a ...

AlgebraB-2 - I need help with figuring out how to do these problems to get the ...

AlgebraB-2 - Thanks everybody, I got a solution for figuring out the answer (...

math - A rocket is launch from the top of an 40 foot cliff with an initial ...

physics - A stationary rocket is launched vertically upward. After 4s, the ...

Math - A rocket is launched upward and then falls to the ground. The height of ...

Math/calculus - a toy rocket is shot into the air at the top of a building so ...

math - A model rocket is launched with an initial velocity of 160 ft/s. The ...

math - A model rocket is launched with an initial velocity of 250 ft/s. The ...