calculus
posted by Mhd on .
find the slope of the tangent line at the point (1,2) for the ellipse 2x^2+3y^2=14
y'(1) = ??

differentiate implicitly
4x + 6y dy/dx = 0
dy/dx = 6y/(4x) = 3y/(2x)
sub in (1,2) to get the slope
take it from there