Posted by BreAnne on .
can I please have help with these 3 questions?
1. Solve this equation graphically on the interval [0, 2ð]. list the solutions.
sin(2x)1=tan x
2. solve sin x cos x= sqrt3/4
3. solve tan^2 x3tan x+2=0
thank you! show step by step please.

Trig 
Reiny,
1. try
http://www.wolframalpha.com/input/?i=sin%282x%291%3Dtan%28x%29+
2.
sinxcosx = √3/4
times 2
2sinxcosx = √3/2
sin(2x) = √3/2
2x = 60° or 2x = 120°
x = 30° or x = 60°
period of sin 2x is 180°
so other solutions
x = 30 + k(180) and x = 60 + k(180) degrees , where k is an inter
in radians:
x = π/6 + kπ or x = π/3 + kπ
3. let tanx = t
you have t^2  3t + 2 = 0
(t2)(t1) = 0
t = 2 or t = 1
so
tanx = 2 > two answers in domain 0≤x≤2π
or
tanx = 1 > two answers in domain 0 ≤ x ≤ 2
give it a try 
Trig 
BreAnne,
thank you so much!