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Algebra 2

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√(21x^2y/(75xy^5)

it says on my paper to enter it: √b, enter sqrt(b). For example: For 4√3 enter 4sqrt(3)
Please help, I've got 5 wrong! :(

  • Algebra 2 -

    If ã(21x^2y/(75xy^5) mean:

    sqrt ( 21 * x^2 * y / ( 75 * x * y^5))

    then:

    sqrt ( 21 * x^2 * y / ( 75 * x * y^5) ) =

    sqrt ( 3 * 7 * x^2 * y / ( 3 * 25 * x * y^5 ) ) =

    sqrt ( 7 * x / ( 25 * y^4 ) ) =

    sqrt ( 7 x ) / sqrt ( 25 y^4) =

    sqrt ( 7 x ) / 5 y^2

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