Posted by jazz on Thursday, April 12, 2012 at 10:57pm.
The electron in a hydrogen atom with an energy of 0.544 eV is in a subshell with 18 states.
What is the principal quantum number, n, for this atom?
What is the maximum possible orbital angular momentum this atom can have?
Is the number of states in the subshell with the next lowest value of l equal to 16, 14, or 12?

physics  drwls, Friday, April 13, 2012 at 7:22am
Bassed upon the energy level, n^2 = 13.6/.544 = 25, and n = 5. That n state has 2 n^2 = 50 substates.
The maximum orbital angular momentum quantum number for this nvalue is
(lower case L) = n1 = 4. The orbital angular momentum of that state is 4 h, where h is Planck's constant.
For the next lower orbital quantum number of that nstate, L = 3, there are
2*(2L + 1) = 14 subshells.
The L projections are 3, 2, 1, 0, 1, 2 and 3, with two electron spin projections per L projection.
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