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October 25, 2014

October 25, 2014

Posted by **jazz** on Thursday, April 12, 2012 at 10:57pm.

What is the principal quantum number, n, for this atom?

What is the maximum possible orbital angular momentum this atom can have?

Is the number of states in the subshell with the next lowest value of l equal to 16, 14, or 12?

- physics -
**drwls**, Friday, April 13, 2012 at 7:22amBassed upon the energy level, n^2 = 13.6/.544 = 25, and n = 5. That n state has 2 n^2 = 50 substates.

The maximum orbital angular momentum quantum number for this n-value is

(lower case L) = n-1 = 4. The orbital angular momentum of that state is 4 h, where h is Planck's constant.

For the next lower orbital quantum number of that n-state, L = 3, there are

2*(2L + 1) = 14 subshells.

The L projections are -3, -2, -1, 0, 1, 2 and 3, with two electron spin projections per L projection.

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