Posted by Alex on Thursday, April 12, 2012 at 10:32pm.
Did you follow suggestion and sketch the lines?
I see a triangle with vertices
(0,0), (6,3) and (6,-6)
You certainly would not need Calculus for this
base = 9, height = 6
area = (1/2)(9)(6) = 27
If you have to use Calculus ....
effective height = x/2 - (-x) = (3/2)x
area = ∫(3/2) x dx from 0 to 6
= (3/4)x^2 | from 0 to 6
= (3/4)(36) - 0 = 27
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