Posted by Dakota on Thursday, April 12, 2012 at 9:31pm.
I believe to find the sum of the exterior angles of a n-sided polygon is (n-2)*180 where n is the number of sides. So for a 50-sided polygon it should be 8640 degrees. For the interior angles it is (n-2)*180/n where again n is the number of sides.
A small correction:
The sum of the interior angles of an n-gon is (n-2)*180.
The interior angles and the exterior angles always add up to 360.
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