tell me if I am correct. In order to find the sum of the angles in a 50-gon, you have to find the number of triangle in a petagon which is 3 therefore 50-gon would have 30 triangles. then i would take 30 X 180 which would give me 5,400 degree
I believe to find the sum of the exterior angles of a n-sided polygon is (n-2)*180 where n is the number of sides. So for a 50-sided polygon it should be 8640 degrees. For the interior angles it is (n-2)*180/n where again n is the number of sides.
A small correction:
The sum of the interior angles of an n-gon is (n-2)*180.
The interior angles and the exterior angles always add up to 360.
540
That
540
I'm sorry, but your understanding is slightly incorrect. To find the sum of the angles in a polygon, you need to use a different formula.
The sum of the angles in any polygon can be found using the formula: (n - 2) * 180 degrees, where 'n' represents the number of sides in the polygon.
In your case, you have a 50-gon, which means you have a polygon with 50 sides. Applying the formula, you would do the following calculation: (50 - 2) * 180 degrees.
(50 - 2) * 180 = 48 * 180 = 8,640 degrees.
Therefore, the sum of the angles in a 50-gon is 8,640 degrees, not 5,400 degrees.