Homework Help: Chemistry

Posted by Beth on Thursday, April 12, 2012 at 8:34pm.

A solution contains an unknown mass of dissolved barium ions. When sodium sulfate is added to the solution, a white precipitate forms. The precipitate is filtered and dried and found to have a mass of 258 mg. What mass of baium was in the original solution? (Assume that all of the barium was precipitated out of solution by the reaction)

Chemistry - DrBob222, Thursday, April 12, 2012 at 9:00pm
258 mg BaSO4 = 0.258 g.
mols BaSO4 = 0.258/molar mass BaSO4.
mols Ba = same as mols BaSO4,
g Ba = mols x atomic mass Ba

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