Posted by Greg on Thursday, April 12, 2012 at 6:51pm.
What is the first term of a geometric series with a summation of 800, 4 terms and a common ratio of 3?

Algebra 2  Steve, Friday, April 13, 2012 at 12:43pm
easy way:
1,3,9,27 adds to 40
800/40 = 20
so, 20,60,180,540
or,
a(1+r+r^2+r^3) = a(r^41)/(r1) = a*80/2 = 40a
so, a = 800/40 = 20

Algebra 2  Greg, Saturday, April 14, 2012 at 1:15pm
Thank you, I think I understand how to work it out now! That helped me out so much!
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