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posted by Sydney on Thursday, April 12, 2012 at 6:03pm.
A 100 mL sample of 0.10M HCl is mixed with 50mL of 0.10M NH3 (Kb=1.8x10^-5). What is the resulting pH?
mols HCl = M x L = ? mols NH3 = M x L = ? Subtract mols HCl-mols NH3, then pH = -log(H^+)
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