Friday

February 27, 2015

February 27, 2015

Posted by **Michael** on Thursday, April 12, 2012 at 4:56pm.

The integral from 0 to the square root of 2 over 2 of the function 8/sq. rt.(1-t^2)

- Calculus -
**Steve**, Thursday, April 12, 2012 at 5:24pmAnother standard:

∫dx/√(1-x^2) = arcsin(x)

sin pi/4 = √2/2

Crank thou onward . . .

**Answer this Question**

**Related Questions**

Calculus - Evaluate the integral. The integral from the square root of three ...

calculus - how do you solve the integral of 1/[(square root of x)(lnx)] from 2 ...

Calculus - Find the exact area of the region enclosed by the square root of (x...

Calculus II/III - A. Find the integral of the following function. Integral of (x...

Calculus - Evaluate integral of x times the square root of (x-4) dx I got u-(8u...

Calculus integral - evaluate the integral: integral from -pi/4 to 0 for the ...

calculus - 8). Part 1 of 2: In the solid the base is a circle x^2+y^2=16 and the...

calculus - consider the function f(x) = e^x(sinNx) on the interval [0,1] where N...

calculus - consider the function f(x) = e^x(sinNx) on the interval [0,1] where N...

Calculus - Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if ...