Saturday
March 25, 2017

Post a New Question

Posted by on .

Evaluate the integral.

The integral from the square root of three over three to the square root of three of the function 6/(t^2+1)

  • Calculus - ,

    This is one of your standard integrals:

    ∫dx/(x^2+1) = arctan(x)

    now, what angle θ has tanθ = √3/3?
    θ = pi/6

    Now go and crank on it. If you get stuck, come on back.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question