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Posted by on Thursday, April 12, 2012 at 3:55pm.

When you take your 1300-kg car out for a spin, you go around a corner of radius 57.7 m with a speed of 16.5 m/s. The coefficient of static friction between the car and the road is 0.93. Assuming your car doesn't skid, what is the force exerted on it by static friction?

  • circular motion - , Thursday, April 12, 2012 at 4:00pm

    Idk

  • circular motion - , Thursday, April 12, 2012 at 4:02pm

    Centripetal force comes from friction:

    what is mass*velocity squared divided by radius? That is the force directed inward.

    The last data in the problem is not revelant.

  • circular motion - , Wednesday, February 20, 2013 at 4:39pm

    6134

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