Posted by samantha on Thursday, April 12, 2012 at 3:51pm.
This is (probably) a series with a recurrence relation:
a(n)=a(n-3)+a(n-2)+a(n-1)
Try
0=-1+0+1
1=0+1+0
2=1+0+1
...
37=6+11+20
Some call this tribonacci numbers, from
Fibonacci numbers where
a(n)=a(n-2)+a(n-1)
Thanks so much
How do get the three numbers relative I understand that the number u get is the first to add for the next in the pattern?
Are the three numbers 63. 89. 115???????
Basically, you add the three last numbers to get the next, for example,
2+3+6=11, ...
So the next number is:
11+20+37 = 68
20+37+68 = ?
...
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