posted by casey on .
write and equation for the reaction of triethylamine and water. does the eqilibrium go to the right or left.
so far what I have is C6H15N + H2O
but I'm not sure of the products
Triethyl amine is a base; therefore, it accepts a proton (from H2O) which releases the OH^-
(CH3CH2)3N + HOH ==> (CH3CH2)3NH^+ + OH^-