Posted by Anonymous on Thursday, April 12, 2012 at 1:56pm.
a projectile is fired at an angle of 60 degrees with the horizontal and with the initital velocity of 80 m/s. What is the time of flight? What is the max height attained and the time taken to attain it? What is the range? The velocity of projection 2 seconds after being fired?

physics  Elena, Thursday, April 12, 2012 at 2:21pm
t = 2•v(o) •sinα/g,
h= v(o)^2•(sinα) ^2/2•g,
L= v(o)^2•(sin2α)/g,
v(y) = v(oy)  g•t = v(o) •sin α  g•t,
v(x) = v(ox) = v(o) •cos α,
v = sqrt[v(x)^2 + v(y)^2]

physics  bobpursley, Thursday, April 12, 2012 at 2:29pm
Elena: Your answers are very good. If you are interested in joining our volunteer teachers, please click on the contact us link at the bottom.
Thanks.
Bob Pursley

physics  Elena, Thursday, April 12, 2012 at 6:18pm
To Bob Pursley
Thank you for your kind words. I'm ready to join to your team with great pleasure
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