Posted by Anonymous on .
a projectile is fired at an angle of 60 degrees with the horizontal and with the initital velocity of 80 m/s. What is the time of flight? What is the max height attained and the time taken to attain it? What is the range? The velocity of projection 2 seconds after being fired?
t = 2•v(o) •sinα/g,
h= v(o)^2•(sinα) ^2/2•g,
v(y) = v(oy) - g•t = v(o) •sin α - g•t,
v(x) = v(ox) = v(o) •cos α,
v = sqrt[v(x)^2 + v(y)^2]
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To Bob Pursley
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