Posted by **Anonymous** on Thursday, April 12, 2012 at 1:56pm.

a projectile is fired at an angle of 60 degrees with the horizontal and with the initital velocity of 80 m/s. What is the time of flight? What is the max height attained and the time taken to attain it? What is the range? The velocity of projection 2 seconds after being fired?

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**Elena**, Thursday, April 12, 2012 at 2:21pm
t = 2•v(o) •sinα/g,

h= v(o)^2•(sinα) ^2/2•g,

L= v(o)^2•(sin2α)/g,

v(y) = v(oy) - g•t = v(o) •sin α - g•t,

v(x) = v(ox) = v(o) •cos α,

v = sqrt[v(x)^2 + v(y)^2]

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**bobpursley**, Thursday, April 12, 2012 at 2:29pm
Elena: Your answers are very good. If you are interested in joining our volunteer teachers, please click on the contact us link at the bottom.

Thanks.

Bob Pursley

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**Elena**, Thursday, April 12, 2012 at 6:18pm
To Bob Pursley

Thank you for your kind words. I'm ready to join to your team with great pleasure

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