Posted by **Anonymous** on Thursday, April 12, 2012 at 1:39pm.

a projectile is fired at an angle of 60 degrees with the horizontal and with the initital velocity of 80 m/s. What is the time of flight?

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**Elena**, Thursday, April 12, 2012 at 1:48pm
t = 2•v(i) •sin(2α)/g

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**Elena**, Thursday, April 12, 2012 at 1:52pm
Sorry!

t = 2•v(i) •sin(α)/g

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**drwls**, Thursday, April 12, 2012 at 2:25pm
Elena's second answer for the time of flight is correct. The angle 2á enters when calculating the range.

In your case, á = 60 degrees

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