posted by Dylan on .
The reaction described by the equation
Zn + Hg2Cl2 <--> 2Hg +Zn+2 + 2Cl is run on electrochemical cell. The E^0 of the cell at 25 degrees C is 1.03V. In the same cell, [Cl-]=.10 M and [Zn+2] is unknown, and the measured cell voltage is 1.21V. Compute the value of [Zn+2] in the cell solution.
Ecell = Eocell - (0.0592/2)log(Q)
Ecell you know.
Eocell you know.
Q = (products)/(reactants) and each coefficent becomes an exponent.
Solve for the one unknown.