The device called an At-woods machine.if m2 is greatr than m1 an assumng th pulley to be frictionless and massless.1.how far will m2 fall in th time T aftr the system is released? 2.what is th tension in the cord that connect two massess? 3. If m1=5kg and m2=3kg,what is the tension in the cord? 4. What is the time needed for the masses to move 15m from rest?
if you had written the separate equations of motion for m1 and m2, recognizing that the acceleration a is the same for both, you would find that
the acceleration rate is:
a = (m2 - m1)g/(m1 + m2)
1. S = (1/2)a*T^2 is the distance moved
2. T = m2(a + g)
= 2(m1*m2)g/(m1 + m2)
(same on both sides)
3. Plug in the m1 amd m2 numbers
4. Solve (1/2)a*T^2 = 15 m for T