Posted by **Toivo** on Thursday, April 12, 2012 at 6:02am.

The device called an At-woods machine.if m2 is greatr than m1 an assumng th pulley to be frictionless and massless.1.how far will m2 fall in th time T aftr the system is released? 2.what is th tension in the cord that connect two massess? 3. If m1=5kg and m2=3kg,what is the tension in the cord? 4. What is the time needed for the masses to move 15m from rest?

- physics -
**drwls**, Thursday, April 12, 2012 at 7:17am
if you had written the separate equations of motion for m1 and m2, recognizing that the acceleration a is the same for both, you would find that

the acceleration rate is:

a = (m2 - m1)g/(m1 + m2)

1. S = (1/2)a*T^2 is the distance moved

2. T = m2(a + g)

= 2(m1*m2)g/(m1 + m2)

(same on both sides)

3. Plug in the m1 amd m2 numbers

4. Solve (1/2)a*T^2 = 15 m for T

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