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October 21, 2014

October 21, 2014

Posted by **Toivo** on Thursday, April 12, 2012 at 6:02am.

- physics -
**drwls**, Thursday, April 12, 2012 at 7:17amif you had written the separate equations of motion for m1 and m2, recognizing that the acceleration a is the same for both, you would find that

the acceleration rate is:

a = (m2 - m1)g/(m1 + m2)

1. S = (1/2)a*T^2 is the distance moved

2. T = m2(a + g)

= 2(m1*m2)g/(m1 + m2)

(same on both sides)

3. Plug in the m1 amd m2 numbers

4. Solve (1/2)a*T^2 = 15 m for T

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