Posted by Jake on Thursday, April 12, 2012 at 3:21am.
Sketch the graph: (x+2)^2/25(y+4)^2/25=1
I don't understand this at all! When I tried graphing it I just had two lines going through the center, which is (2,4). But it should be a hyperbola, right? Could anyone help me?

Math help  Steve, Thursday, April 12, 2012 at 11:19am
hyperbola
center at (2,4)
eccentricity = √2
asymptotes y+4 = ±(x+2)
vertices at x = ±2.5
foci at x = ±5√2

Math help  PS  Steve, Thursday, April 12, 2012 at 11:22am
Oops
vertices at (2±5,4)

Math help  Jake, Thursday, April 12, 2012 at 11:39am
So do I draw lines through the vertices?
Answer This Question
Related Questions
 math,help  i need help with this one i've tried it many ways and still can't ...
 math30  The equation of the hyperbola is (x3)^2/4  (y+1)^2/16 =1. What is ...
 cal  Equations of the tangent lines to hyperbola xy=1 that pass through point...
 Parabola/Hyperbola  Not really for homework help, but just for curiousity. Is ...
 algebra  Can someone check my answers on exploring conic sections? 1. Graph x2...
 Calculus  a)The curve with equation: 2y^3 + y^2  y^5 = x^4  2x^3 + x^2 has ...
 Precalc  Heres the equation: (x^2)(4y^2)(4x)+(24y)(36)=0 Your supposed to ...
 calculus  i'm not sure how to do this. can someone help, please? thanks! ...
 math  The function f(x)= ax^3  bx +c passes through the origin, f(1)=4/3 and ...
 Trigonometry  I'm having a lot of trouble with graphing trig functions. Can ...
More Related Questions