Posted by Julie on Thursday, April 12, 2012 at 12:28am.
f'(x) = 1+ 2cosx(-sinx)
f(π/4) = π/4 + cos^2 (π/4) = π/4 + 1/2 = (2+π)/4
f'(π/4) = 1 + 2(1/√2)(-1/√2) = 1 - 2/2 = 0
so the line is horizontal and its equation is simply
y = (2+π)/4
check my arithmetic, (did not write it down first)
Thanks Reiny, I have checked it over and it seems about right to me. Thank you.
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