Posted by Julie on Thursday, April 12, 2012 at 12:27am.
chain rule:
d/dx sin^2 x = 2(sinx)(cosx) = sin2x
a)
y = (x^2+x-1)sin^2 x
y' = (2x+1)sin^2 x + (x^2+x-1)sin2x
b)
y = (x^2+1)/sin^2 x
y = (2x*sin^2 x - (x^2+1)*2*sinx*cosx]/sin^4 x
= [2x*sinx - (x^2+1)*cosx]/sin^3 x
Thank you Steve
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