Find a counterexample to show that the conjecture is false. Any number that is divisible by 5 is also divisible by 3.
A.
45
B.
60
C.
30
D.
25
I'll be glad to check your answer.
Which of your choices is NOT divisible by 3?
What is the answer Ms. sue
30
To find a counterexample to show that the conjecture is false, we need to find a number that is divisible by 5 but not divisible by 3. Let's go through the given options:
A. 45: This number is divisible by 5, but it is also divisible by 3 (45 ÷ 3 = 15), so it does not serve as a counterexample.
B. 60: This number is divisible by both 5 and 3 (60 ÷ 5 = 12 and 60 ÷ 3 = 20), so it does not serve as a counterexample either.
C. 30: This number is divisible by both 5 and 3 (30 ÷ 5 = 6 and 30 ÷ 3 = 10), so it does not work as a counterexample either.
D. 25: This number is divisible by 5 (25 ÷ 5 = 5), but it is not divisible by 3. Therefore, 25 serves as a counterexample to the conjecture, as it is divisible by 5 but not by 3.
Thus, the correct answer is option D.