Select the equation that solves this problem:

Eight coins (dimes and quarters) are worth 170 cents. How many dimes are
there?
a. 10d + 25(11 - d) = 170
b. 10d + 25(8 - d) = 170
c. 10d + 5(8 - d) = 60
d. 10d + 5(11 - d) = 60

So what do you think?

I send to you solution for simmilar problem.

A quarters is worth 25 cents and a dime is worth 10 cents.

q = numbers of a quarters

d = numbers of a dimes

q + d = 8

q = 8 - d

Value of money :

10 ¢ * d + 25 ¢ * q = 170 ¢

10 d + 25 q = 170

10 d + 25 ( 8 - d ) = 170

Equation b.

10 d + 25 ( 8 - d ) = 170

10 d + 25 * 8 + 25 * ( - d ) = 170

10 d + 200 - 25 d = 170

10 d - 25 d = 170 - 200

- 15 d = - 30 Divide both sides by - 15

d = - 30 / - 15

d = 2

q = 8 - d = 8 - 2 = 6

2 dimes and 6 quarters

2 * 10 ¢ + 6 * 25 ¢ =

20 ¢ + 150 ¢ = 170 ¢

To solve this problem, we need to set up an equation that represents the given information. Let's use the letter "d" to represent the number of dimes.

We know that eight coins (dimes and quarters) are worth 170 cents. Since dimes are worth 10 cents each and quarters are worth 25 cents each, we can write the equation:

10d + 25(8 - d) = 170

Now let's break down the equation:

- The term "10d" represents the total value of dimes (10 cents times the number of dimes, d).
- The term "25(8 - d)" represents the total value of quarters (25 cents times the number of quarters, which is the remaining 8 - d coins).

The sum of these two terms is equal to 170 cents, which represents the total value of the eight coins.

Therefore, the correct equation that solves this problem is:

a. 10d + 25(11 - d) = 170