Posted by **Cheril** on Wednesday, April 11, 2012 at 8:00pm.

Select the equation that solves this problem:

Eight coins (dimes and quarters) are worth 170 cents. How many dimes are

there?

a. 10d + 25(11 - d) = 170

b. 10d + 25(8 - d) = 170

c. 10d + 5(8 - d) = 60

d. 10d + 5(11 - d) = 60

- math -
**bobpursley**, Wednesday, April 11, 2012 at 8:05pm
So what do you think?

- math -
**Bosnian**, Wednesday, April 11, 2012 at 8:08pm
I send to you solution for simmilar problem.

- math -
**Bosnian**, Wednesday, April 11, 2012 at 8:25pm
A quarters is worth 25 cents and a dime is worth 10 cents.

q = numbers of a quarters

d = numbers of a dimes

q + d = 8

q = 8 - d

Value of money :

10 ¢ * d + 25 ¢ * q = 170 ¢

10 d + 25 q = 170

10 d + 25 ( 8 - d ) = 170

Equation b.

10 d + 25 ( 8 - d ) = 170

10 d + 25 * 8 + 25 * ( - d ) = 170

10 d + 200 - 25 d = 170

10 d - 25 d = 170 - 200

- 15 d = - 30 Divide both sides by - 15

d = - 30 / - 15

d = 2

q = 8 - d = 8 - 2 = 6

2 dimes and 6 quarters

2 * 10 ¢ + 6 * 25 ¢ =

20 ¢ + 150 ¢ = 170 ¢

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