Posted by curtis on Wednesday, April 11, 2012 at 6:54pm.
Find mols NaOH, subtract mols HBr.
If mols NaOH are greater then pOH = -log(OH^-) and convert to pH by
pH + pOH = pKw = 14.
If mols HBr are in excess, pH = -log(H^+).
Those three steps will do all of the points except for the equivalence point. That one is done by the hydrolysis of the salt, NaBr, which is 7 at the equivalence point.
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