Monday

March 2, 2015

March 2, 2015

Posted by **anonymous** on Wednesday, April 11, 2012 at 1:51pm.

3.49

The temperature of the system is reduced, keeping the volume constant at 3 liters, until the pressure of the gas in the system equals 13 atm. Call this new state of the system B. Calculate the temperature at this new state B in degrees K.

1.36×102

Now allow the gas to expand at constant pressure (13 atm) until the temperature is again equal to 356K. Call this state of the system C. Calculate the volume of the gas at state C. Enter your answer as a volume in liters.

7.85

Now calculate the work done on or by the system when the system moves back from state C to state A along the path CBA. Enter your answer in joules with the correct sign.

Calculate the heat absorbed or liberated by the system when the system moves from state C to state B. Enter your answer in joules with the correct sign.

Using your results from the previous two questions, calculate the heat absorbed or liberated by the system as the system moves from state B to state A. Enter your answer in joules with the correct sign.

It is possible to move from state C to state A in two stages via an alternative state D. The first step, from state C to state D involves increasing the pressure at constant volume until the pressure equals the original 34 atm. Calculate the temperature at the state D in degrees K.

Calculate the heat released or absorbed by the system as the system moves from state C to state D. Enter your answer in joules with the correct sign.

Calculate the work done on or by the system as it changes from state D to state A -- a change in volume at a constant pressure of 34 atm. Enter your answer in joules with the correct sign.

Use your answers to the previous two questions to calculate the heat change when the system moves from state D to state A. Enter your answer in joules with the correct sign.

if you just give me the formulas I should be able to figure it out. Please help me

- physics -
**Elena**, Thursday, April 12, 2012 at 4:31am1. pV =νRT

34 atm = 3445050 Pa

ν = pVRT = 3445050• 3•10^-3/8.31•356 = 3.49 mol

2.

V1=V2

p1 /T1 = p2 /T2

T2 =p2•T1/p1 =13•356/34 = 136 K

3. V1/T1 = V2/T2

V2 = V1•T2/T1 =3•356/ 136= 7.85 L

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