Some air at 275 kPa absolute pressure occupies 50.0m^3. Find its absolute pressure if its volume is doubled at constant temperature.

p1•V1/T1 = p2•V2/T2

T1 = T2
p1•V1= p2•V2
p1 =275000 Pa
V1 = 50 cm3 =5•10^-5 m3
V2 =2 V1
p2 = p1•V1/V2

To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. The equation for Boyle's Law is:

P₁V₁ = P₂V₂

Where:
P₁ = Initial pressure (275 kPa)
V₁ = Initial volume (50.0 m³)
P₂ = Final pressure (to be determined)
V₂ = Final volume (double the initial volume)

Let's plug in the given values into the equation and solve for P₂:

P₁V₁ = P₂V₂

(275 kPa)(50.0 m³) = P₂(2V₁)

13750 kPa*m³ = 2P₂(50.0 m³)

13750 kPa*m³ = 100P₂

To find P₂, we can divide both sides of the equation by 100:

137.5 kPa = P₂

Therefore, the absolute pressure of the air when its volume is doubled at constant temperature is 137.5 kPa.

To find the absolute pressure after the volume is doubled at constant temperature, you can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when temperature is held constant. Boyle's Law can be mathematically expressed as:

P₁V₁ = P₂V₂

Where:
P₁ = initial pressure (275 kPa)
V₁ = initial volume (50.0 m³)
P₂ = final pressure (unknown)
V₂ = final volume (double the initial volume, i.e., 2 * 50.0 m³)

Substituting the known values into the equation, we get:

275 kPa * 50.0 m³ = P₂ * (2 * 50.0 m³)

Simplifying the equation, we have:

13750 = P₂ * 100

To solve for P₂, divide both sides of the equation by 100:

P₂ = 13750 / 100
P₂ = 137.5 kPa

Therefore, the absolute pressure of the air after the volume is doubled at constant temperature is 137.5 kPa.