Phys
posted by Sara on .
Some propane occupies 150 cm^3 at 12.4°C. Find the temperature when its volume is 132ft^3 if the pressure remains constant.

p1•V1/T1 = p2•V2/T2
p1 = p2
V1/T1 = V2/T2
V1 = 150 cm3 =0.00015 m3
T1 =273 +12.4 = 285.4 K
V2 =132 ft3 = 3.738 m3
T2 = V2•T1/V1