how many grams of ammonia (NH3) will react with 27.8 grams of nitric oxide (NO)?
4NH3 + 6NO d 5N2 + 6H2O
How many mols NO do you have? That's mols = grams/molar mass
Convert mols NO to mols NH3.
Finally convert mols NO to grams NO. g = mols x molar mass.
To determine the number of grams of ammonia (NH3) that will react with 27.8 grams of nitric oxide (NO), we need to understand the stoichiometry of the balanced chemical equation provided.
The balanced equation for the reaction is:
4NH3 + 6NO -> 5N2 + 6H2O
From the equation, we can see that 4 moles of NH3 react with 6 moles of NO. These coefficients represent the molar ratio between the reactants and products.
To calculate the number of moles of NO, we divide the given mass by its molar mass. The molar mass of NO is approximately 30 grams/mol.
Number of moles of NO = mass of NO / molar mass of NO
Number of moles of NO = 27.8 g / 30 g/mol
Number of moles of NO ≈ 0.927 mol
Based on the stoichiometry of the balanced equation, we can set up a ratio between the number of moles of NH3 and NO.
From the balanced equation,
4 moles of NH3 react with 6 moles of NO.
Therefore, the ratio between NH3 and NO is:
4 moles NH3 / 6 moles NO
Now, we can use this ratio to find the number of moles of NH3 that will react:
Number of moles of NH3 = ratio * number of moles of NO
Number of moles of NH3 = (4/6) * 0.927 mol
Number of moles of NH3 ≈ 0.618 mol
Finally, to find the mass of NH3 that will react, we multiply the number of moles by its molar mass. The molar mass of NH3 is approximately 17 grams/mol.
Mass of NH3 = number of moles of NH3 * molar mass of NH3
Mass of NH3 = 0.618 mol * 17 g/mol
Mass of NH3 ≈ 10.5 grams
Therefore, approximately 10.5 grams of ammonia (NH3) will react with 27.8 grams of nitric oxide (NO).