Volume of 1200 L of helium at 4000 Pa is heated from 45.0°C to 75.0°C increasing the pressure to 6000 Pa. What is the resulting volume of gas?

p1•V1/T1 = p2•V2/T2

V1 =1200 L =1200•10^-3 m^3
T1 =273 +45 = 318 K
T2 =273 +75 = 348 K
V2 = p1•V1•T2/p2•T1

To find the resulting volume of gas, you can use the combined gas law equation:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature (in Kelvin)
P2 = final pressure
V2 = final volume (what we want to find)
T2 = final temperature (in Kelvin)

First, let's convert the temperatures from Celsius to Kelvin:
T1 = 45.0°C + 273.15 = 318.15 K
T2 = 75.0°C + 273.15 = 348.15 K

Now, let's plug in the given values:
P1 = 4000 Pa
V1 = 1200 L
P2 = 6000 Pa
T1 = 318.15 K
T2 = 348.15 K

Using the formula, we have:
(4000 * 1200) / (318.15) = (6000 * V2) / (348.15)

Now we can solve for V2:
(4000 * 1200 * 348.15) / (318.15 * 6000) = V2

Calculating the above expression will give us the resulting volume of gas, V2.