Posted by srikala on Wednesday, April 11, 2012 at 9:17am.
What do you mean by "completes motion along a vertical line" ? Does the bob go straight up and stop?
yes the bob goes straight up and stops
Let Vf be the bob velocity just after the bullet has gone through, before it has started to swing upwards.
(1/2)Vf^2 = 2 g l
(from conservation of energy)
Vf = sqrt (4 g*l) = 2 sqrt(g*l)
Now apply conservation of momentum to the bullet interaction:
m1*v1 = m1*(v1/3) + m*Vf
(2/3)m1*v1 = 2*m*sqrt(g*l)
v1 = 3(m/m1)*sqrt(g*l)
What if the motion of the bob after collision just complete along a vertical circle??
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