Posted by myra on Wednesday, April 11, 2012 at 8:23am.
THe monkey is putting a tension on the rope of mg+ma. THe opposite monkey is putting a tension of -mg. The resultant force on the rope is ma.
F=ma
ma= (2m)A
A= 1/2 a
Therefore, both monkeys accelerate upwards at the same rate, which is half the rate as the acceleration (relative to the rope) as the climbing monkey. In short, the other monkey goes up.
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