Posted by **aisya** on Wednesday, April 11, 2012 at 4:30am.

a bullet is fired from the ground at the angle of 30 degree above the horizontal,What initial speed must the bullet have in order to hit a point 250 ft high on a tower located 400 ft away (ignoring air resistance),what the solution?

- physic -
**drwls**, Wednesday, April 11, 2012 at 8:05am
Write vertical and horizontal equations of motion. Require that X = 400 and Y = 250 at same time, t. You have two equations for the two unknowns, t and Vo. They are:

X = Vo*cos30 * t = 400

Y = Vo*sin30 * t - (g/2) t^2 = 250

I recommend using the X equation to substitute for t in the second (Y) equation.

g = 32.2 ft/s^2.

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