The sum of two numbers is 100. One number is four more than three time the other number. What are the last numbers?
x = first number
3x + 4 = second number
Therefore:
x + 3x + 4 = 100
Solve for x.
Don't forget to list both numbers!
x + 3x + 4 = 100
4x = 96
x = ?
by transferring 4 to other side
x=96/4
x=24
To find the two numbers, let's assign variables to them. Let's call the first number x and the second number y.
From the given information, we can create two equations:
Equation 1: x + y = 100 (the sum of the two numbers is 100).
Equation 2: x = 3y + 4 (one number is four more than three times the other number).
Now we can solve this system of equations to find the values of x and y.
Substitute the value of x from Equation 2 into Equation 1:
(3y + 4) + y = 100
4y + 4 = 100
Subtract 4 from both sides:
4y = 96
Divide both sides by 4:
y = 24
Now substitute the value of y back into Equation 1 to find x:
x + 24 = 100
Subtract 24 from both sides:
x = 76
Therefore, the two numbers are 76 and 24.