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September 16, 2014

September 16, 2014

Posted by **tabby** on Tuesday, April 10, 2012 at 6:07pm.

I was not taught how to graph a function like this, only the simple y= sin x and y= cos x functions. Please help me. you do not have to provide a graph as long as you clearly explain how i would put it on a graph.

as a note: the graph i have has x values of 0 to 2pi and y values of 4 to -4. Thank you and God bless!

- trig/precalc -
**bobpursley**, Tuesday, April 10, 2012 at 6:16pmy= A sin Theta

you can graph that. Now let A= 3.55

Now let theta= x-PI/4

That means theta is zero when x=PI/4. So it is a sine curve shifted to the right by PI/4

You can plot that.

- trig/precalc -
**tabby**, Tuesday, April 10, 2012 at 6:20pmbobpursely: Thank you so much! God bless you for taking the time to help!

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