What mass of sodium chloride is produced when chlorine gas reacts with 0.29 grams of sodium iodide? Unbalanced equation is given below:
NaI + Cl2 -> NaCl + I2
Balance the equation.
Convert 0.29 g NaI to mols. mols = grams/molar mass
Use the coefficients in the balanced equation to convert mols NaI to mols NaCl.
Now convert mols NaCl to grams. g = mols x molar mass.
To calculate the mass of sodium chloride produced, we need to use stoichiometry and balance the equation first.
NaI + Cl2 -> NaCl + I2
Now, let's balance the equation:
2NaI + Cl2 -> 2NaCl + I2
From the balanced equation, we can see that 2 moles of NaI react with 1 mole of Cl2 to produce 2 moles of NaCl.
Step 1: Convert the mass of sodium iodide to moles.
Using the molar mass of NaI (22.99 g/mol for Na + 126.9 g/mol for I), we can calculate the number of moles of NaI:
0.29 g NaI * (1 mol NaI / 149.89 g NaI) = 0.00194 moles NaI
Step 2: Use the balanced equation to determine the ratio between NaI and NaCl.
From the balanced equation, we know that 2 moles of NaI produce 2 moles of NaCl.
Step 3: Calculate the mass of NaCl produced.
Since 2 moles of NaI produce 2 moles of NaCl, the ratio is 1:1. So, the number of moles of NaCl produced would be the same as the number of moles of NaI: 0.00194 moles.
Now, we can use the molar mass of NaCl (22.99 g/mol for Na + 35.45 g/mol for Cl) to calculate the mass of NaCl:
0.00194 moles NaCl * 58.44 g NaCl/mol = 0.113 grams NaCl
Therefore, the mass of sodium chloride produced when chlorine gas reacts with 0.29 grams of sodium iodide is 0.113 grams.
To find the mass of sodium chloride produced when chlorine gas reacts with sodium iodide, we need to balance the chemical equation and calculate the molar masses of the compounds involved.
First, let's balance the equation:
2NaI + Cl2 -> 2NaCl + I2
Now, let's calculate the molar masses:
- Sodium iodide (NaI): Na = 22.99 g/mol, I = 126.90 g/mol
- Chlorine gas (Cl2): Cl = 35.45 g/mol (since it exists as a diatomic molecule)
- Sodium chloride (NaCl): Na = 22.99 g/mol, Cl = 35.45 g/mol
Next, we need to convert the mass of sodium iodide given (0.29 grams) to moles. We use the following formula:
moles = mass / molar mass
moles of NaI = 0.29 g / (22.99 g/mol + 126.90 g/mol)
moles of NaI ≈ 0.29 g / 149.89 g/mol
moles of NaI ≈ 0.001934 mol
According to the balanced equation, the mole ratio between NaI and NaCl is 2:2. Therefore, the number of moles of NaCl produced will also be 0.001934 mol.
Finally, we can calculate the mass of sodium chloride produced using the following formula:
mass = moles × molar mass
mass of NaCl = 0.001934 mol × (22.99 g/mol + 35.45 g/mol)
mass of NaCl = 0.001934 mol × 58.44 g/mol
mass of NaCl ≈ 0.1128 g
Therefore, approximately 0.1128 grams of sodium chloride will be produced when chlorine gas reacts with 0.29 grams of sodium iodide.