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March 29, 2017

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A 12 kg toboggan is pulled along at a constant velocity on a horizontal surface by a horizontal force of 11 N

How much horizontal force is needed to pull the toboggan at a constant velocity if two 57 kg girls are sitting in it ?

  • physics - ,

    The projections of the equation of motion are
    x: F – F(fr) = 0
    y: N - m• g = 0

    F = F(fr) = K• N= k• m• g.
    k = F/m• g = 11/(12•9.8) = 0.093.

    The projections of the equation of motion in the second case are
    x: F1 – F1(fr) = 0
    y: N - M• g = 0
    F1 = F1(fr) = k• N1 =k• M• g = 0.093• (2•57+)•9.8 = 114.8 N

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