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March 1, 2015

March 1, 2015

Posted by **mabel** on Tuesday, April 10, 2012 at 11:53am.

- calculus -
**Steve**, Tuesday, April 10, 2012 at 3:46pmdy/dx = 3xy

dy/y = 3x dx

ln y = 3x^2/2+c

y = Ce^3x^2/2

2 = Ce^0

C = 2

y = 2e^(3x^2/2)

y' = 2e^(3x^2/2)*(3x)

= 3xy

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