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December 20, 2014

December 20, 2014

Posted by **Priscilla** on Tuesday, April 10, 2012 at 11:16am.

** (sq root)

y = (square root) x + (2nd sq root) x +

(3rd sq root) x

** All the x's is under three sq roots

y' = 1/2(sq rt) x + 1/(sq rt) x +

3/2(sq rt) x

Is this right?

- Calculus I -
**Bosnian**, Tuesday, April 10, 2012 at 11:25amGo on: wolframalpha dot com

When page be open in rectangle type:

derivative your expresion

and click option =

After few seconds when you see result click option:

Show steps

If square root) x + (2nd sq root) x +

(3rd sq root) x

mean

sqrt(x )+2*sqrt(x)+3*sqrt(x)

type:

derivative sqrt(x )+ 2* sqrt(x)+3*sqrt(x)

and click option =

then

Show steps

On wolfram alpha dot com you can practice any kind ofCalculus

- Calculus I -
**Priscilla**, Tuesday, April 10, 2012 at 11:32amok thank you

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