Sunday
April 20, 2014

Homework Help: Chemistry

Posted by Katherine on Tuesday, April 10, 2012 at 2:41am.

A 0.450-gram sample of impure CaCO3(s) is dissolved in 50.0 mL of 0.150 M HCl(aq). The equation for the reaction is:
CaCO3(s)+2HCl(aq) -> CaCl2(aq) + H2O(l) + CO2(g)

The excess HCl(aq) is titrated by 9.75 mL of 0.125 M NaOH(aq). Calculate the mass percentage of CaCO3(s) in the sample.



Here's what I did. Is this correct? If not how do I approach it?:
excess HCl - x/.00975 L = 0.125 M
x = .00121875 mol

total HCl - x/0.05 L = 0.150 M
x = 0.0075 mol

0.0075 - 0.00121875 mol = 0.00628125 mol
0.00628125 mol HCl X 1mol CaCO3/2mol HCl X 100.0869 g/1 mol CaCO3 = 0.3143 g
0.3143 g/0.450 g = 69.8%?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

chemistry - A 0.5215 gram sample of CaCO3 is dissolved in 12M HCl and the ...
chemistry - CrCl3(s) + AgNO3 (aq)= AgCl(s) + Cr(NO3)3(aq) A 0.750 g sample of ...
Analytical chemistry - A 0.6334 gram of sample of impure mercury (II) oxide was ...
College Chem - Impure sample of table salt that weighed 0.8421g, when dissolved ...
chemistry - A 0.5215 gram sample of CaCO3 is dissolved in 12M HCl and the ...
science - 1.)A sample of ammonium nitrate contains 70 g of nitrogen.what is the ...
College-Chemistry - NaOH(s)+ H2SO4(aq)=Na2SO4(aq) + H2O(l) Consider the ...
chemistry - Assuming that 0.5 grams of a 1.0 gram sample is CaCO3, what should ...
Chemistry - A 25.00 ml sample of a standard solution containing 1 g of CaCO3/L ...
chemistry - in this experiment about recrytallization im having a strange ...

Search
Members