Sunday

December 21, 2014

December 21, 2014

Posted by **sayan** on Tuesday, April 10, 2012 at 12:38am.

into the cup. If the golf ball is launched at a velocity of

20 m/s at an angle of 45° above the horizontal, how far

away was the golfer from the hole when he hit the ball?

What maximum height did the ball reach?

- grade 11 physics -
**drwls**, Tuesday, April 10, 2012 at 1:45amRange = (Vo^2/g)*sin2A

In this case, A = 45 degrees, so

Range = Vo^2/g

(This assumes the ball does not roll in to the cup))

The maximum height, when hit at A = 45 degrees, is such that

H = (Vo sinA)^2/g

= Vo^2/(2g) if A = 45 degrees

**Answer this Question**

**Related Questions**

physics - A golfer hits a golf ball with a velocity of 36.0 meters/second at an ...

physics please help - A golfer, driving a golf ball off the tee, gives the ball ...

MTH 156 - The ratio of the distances a 7-iron and a 5-iron will drive a golf ...

Physics - One of the holes on a golf course lies due east of the tee. A novice ...

physics - A golfer launches a golf ball off a tee that has been raised 24.8 ...

math - the ratio of the distances a 7-iron and a 5- iron will dirve a golf ball ...

math - Write the numbers in order of increasing size. 1/2,3/4,2/3,0.95 Convert ...

Math - A golfer hits ate shot 325 m long straight golf hole. The ball is hooked ...

physics - A golfer tees off and hits a golf ball at a speed of 31 m/s and at an ...

physics - On a distant planet, golf is just as popular as it is on earth. A ...