Posted by **Akbar** on Monday, April 9, 2012 at 8:55pm.

In a hydraulic lift, the radii of the pistons are 2.93 cm and 10.1 cm. A car weighing W = 11.0 kN is to be lifted by the force of the large piston.

(a) What force Fa must be applied to the small piston? 925.7 N

(b) When the small piston is pushed in by 10.4 cm, how far is the car lifted? mm

b. h2 = h1•(A1/A2) = h1•(r/R) = 3.02 cm

(c) Find the mechanical advantage of the lift, which is the ratio W / Fa.

11.9

Sorry for reposting, but i don't know why part b is wrong the answer has to be in mm, so 3.02 cm would be 30.2 mm, but it giving me wrong; please help. Thank you.

## Answer This Question

## Related Questions

- Physics - In a hydraulic lift, the radii of the pistons are 2.93 cm and 10.1 cm...
- Physics - In a hudraulic lift, the radii of the pistons are 2.50 cm and 10.0 cm...
- Physics - The two pistons in a hydraulic lift have radii of 2.67 cm and 20.00 ...
- Physics - The two pistons in a hydraulic lift have radii of 2.67 cm and 20.00 ...
- physics - The small piston of a hydraulic lift has an area of 0.10 m2. A car ...
- Physics - A 104 N car is lifted by a manually operated hydraulic lift. The area ...
- Physics - The pistons of a hydraulic press have radii of 2.00cm and 12.00cm, ...
- Physics - a container weighing a 1.20 x 10^4 N sits on a hydraulic press piston ...
- Hydraulic Physics - In a hydraulic system a 20.0-N force is applied to the small...
- Physics - A hydraulic lift consists of a platform that is supported by a ...

More Related Questions