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In a hydraulic lift, the radii of the pistons are 2.93 cm and 10.1 cm. A car weighing W = 11.0 kN is to be lifted by the force of the large piston.

(a) What force Fa must be applied to the small piston? 925.7 N

(b) When the small piston is pushed in by 10.4 cm, how far is the car lifted? mm

b. h2 = h1•(A1/A2) = h1•(r/R) = 3.02 cm

(c) Find the mechanical advantage of the lift, which is the ratio W / Fa.


Sorry for reposting, but i don't know why part b is wrong the answer has to be in mm, so 3.02 cm would be 30.2 mm, but it giving me wrong; please help. Thank you.

  • physics -

    part b is wrong because you did (A1/A2)=(r/R)

    the ratio of radii should be squared...

  • physics -

    Thank you!

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