Posted by **Mary** on Monday, April 9, 2012 at 8:22pm.

A large solid cylinder rolls without slipping down a 40 m long hill with a 30 degree slope. The cylinder then rolls a short distance over level ground and then off a 20 meter high sheer cliff. How far from the base of the cliff does the cylinder land? Ignore friction and air resistance

- Physics -
**Elena**, Tuesday, April 10, 2012 at 11:23am
The law of conservation of energy

PE =KE,

PE = m•g•h = m•g•s•sinα,

KE = KE1 + KE2 = m•v^2/2 + I•ω^2/2=

= m•v^2/2+ (m•R^2/2) •v^2/2•R^2 =

=3•m•v^2/4.

m•g•s•sinα =3•m•v^2/4.

v = sqrt(4• m•g•s•sinα/3) = 16.2 m/s.

H =gt^2/2, t = sqrt(2•H/g) = 2.02 s.

L =v•t = 16.2 • 2.92 = 32.7 m.

- Physics -
**Mary**, Tuesday, April 10, 2012 at 2:50pm
Thank you so much, Elena!

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