Monday

March 2, 2015

March 2, 2015

Posted by **Mary** on Monday, April 9, 2012 at 8:22pm.

- Physics -
**Elena**, Tuesday, April 10, 2012 at 11:23amThe law of conservation of energy

PE =KE,

PE = m•g•h = m•g•s•sinα,

KE = KE1 + KE2 = m•v^2/2 + I•ω^2/2=

= m•v^2/2+ (m•R^2/2) •v^2/2•R^2 =

=3•m•v^2/4.

m•g•s•sinα =3•m•v^2/4.

v = sqrt(4• m•g•s•sinα/3) = 16.2 m/s.

H =gt^2/2, t = sqrt(2•H/g) = 2.02 s.

L =v•t = 16.2 • 2.92 = 32.7 m.

- Physics -
**Mary**, Tuesday, April 10, 2012 at 2:50pmThank you so much, Elena!

**Answer this Question**

**Related Questions**

physics - In the figure below, a solid cylinder of radius 12 cm and mass 11 kg ...

Physics Classical Mechanics - A hollow cylinder of outer radius R and mass M ...

Physics - A cylinder with a diameter of 16 rolls with an angular speed of 0.055 ...

physics - A cylinder with a diameter of 23 cm rolls with an angular speed of 0....

Physics - A 1-kg thin hoop with a 50-cm radius rolls down a 47° slope without ...

Physics - A uniform solid cylinder of mass M and radius R is at rest on a slab ...

PHYSICS - An 800.0 kg roller coaster car is at rest at the top of a 95 m hill. ...

physics - 4. An 800.0 kg roller coaster car is at rest at the top of a 95 m hill...

Physics - A 1-kg thin hoop with a 50-cm radius rolls down a 47° slope without ...

physics - A solid cylinder of radius 0.85m is released from rest from a height ...