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August 29, 2014

August 29, 2014

Posted by **Antia** on Monday, April 9, 2012 at 8:22pm.

1. Does the line (x-7)/3=(y+8)/6=(z+4)/5 and the point P(10,-2,1) determine a plane?

Answer: Yes, it is a plane because when I substituted the point P(10,-2,1) into the equation, I got the coordinates (1,1,1) If the coordinate became to be (0,0,0) then it wouldn't be a plane.

- Calculus and vectors -
**MathMate**, Monday, April 9, 2012 at 11:18pmL1: (x-7)/3=(y+8)/6=(z+4)/5

When P(10,-2,1) is substituted into L1, we get 1=1=1 which means that P is on the line.

To define a plane from a point and a line, the point must NOT lie on the line else the plane is undefined.

So the answer is*no*, because the point P lies on the given line.

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