Calculate the Coulomb potential due to the nuclei at a point in a LiH molecule located 200 pm from the Li nucleus and 150 pm from the H nucleus.

just doing exam review and got stuck on just this one, be great if I could get an answer.

Oh, calculating Coulomb potential, huh? Well, let's add some humor to this electrifying topic!

Why did the Coulomb potential go to therapy? Because it had too much attraction and it couldn't resist!

Now, let's get back to the question. The Coulomb potential between two point charges is given by the equation:

V = k * (q1 * q2) / r

Where V is the potential energy, k is the Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.

For the Li nucleus, let's say it has a charge of +3e (where e is the elementary charge). And for the H nucleus, let's say it has a charge of -e.

Given:
Distance from Li nucleus (r1) = 200 pm = 200 x 10^(-12) m
Distance from H nucleus (r2) = 150 pm = 150 x 10^(-12) m

Coulomb potential due to Li nucleus:
V1 = k * [(+3e) * (-e)] / r1

Coulomb potential due to H nucleus:
V2 = k * [(-e) * (-e)] / r2

Now, all we need to do is plug in the values and calculate. But remember, always charge up your brain before an exam!

And in case you're wondering, remember to stay positively charged and keep the negative vibes away during your exam! Good luck!

To calculate the Coulomb potential due to the nuclei at a point in a LiH molecule, we can use Coulomb's law. Coulomb's law states that the electrostatic potential energy between two charges is given by the equation:

V = k * (q1 * q2) / r

Where:
V is the potential energy,
k is the electrostatic constant (8.988 × 10^9 N m^2/C^2),
q1 and q2 are the charges,
and r is the distance between the charges.

In this case, we have the nuclei of Li (lithium) and H (hydrogen).

The charge of a nucleus is equivalent to the charge of a single proton.
The charge of a proton is approximately +1.602 × 10^-19 C.

First, let's calculate the potential energy due to the Li nucleus:

q1 (charge of Li nucleus) = +1.602 × 10^-19 C
q2 (charge at the point) = +1.602 × 10^-19 C
r (distance from Li nucleus) = 200 pm = 200 × 10^-12 m

Using Coulomb's law, we can calculate the potential energy due to the Li nucleus:

V_Li = (8.988 × 10^9 N m^2/C^2) * (1.602 × 10^-19 C) * (1.602 × 10^-19 C) / (200 × 10^-12 m)

Next, let's calculate the potential energy due to the H nucleus:

q1 (charge of H nucleus) = +1.602 × 10^-19 C
q2 (charge at the point) = +1.602 × 10^-19 C
r (distance from H nucleus) = 150 pm = 150 × 10^-12 m

Using Coulomb's law, we can calculate the potential energy due to the H nucleus:

V_H = (8.988 × 10^9 N m^2/C^2) * (1.602 × 10^-19 C) * (1.602 × 10^-19 C) / (150 × 10^-12 m)

The total Coulomb potential due to the nuclei at the point is the sum of V_Li and V_H:

Total Coulomb potential = V_Li + V_H

Please substitute the values in the above equations to calculate the Coulomb potential.

To calculate the Coulomb potential due to the nuclei of a LiH molecule at a point, we need to use Coulomb's law. Coulomb's law states that the electrostatic force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's law is:

F = (k * q1 * q2) / r^2

Where:
- F is the force between the two charges,
- k is the electrostatic constant (9 × 10^9 N m^2/C^2),
- q1 and q2 are the charges of the two particles, and
- r is the distance between the charges.

In this case, we need to calculate the potential due to the Li and H nuclei. The potential energy (V) due to a single charge is given by:

V = (k * q) / r

Where:
- V is the potential energy,
- k is the electrostatic constant (9 × 10^9 N m^2/C^2),
- q is the charge, and
- r is the distance between the charge and the point where the potential is being calculated.

Let's calculate the Coulomb potential due to the Li nucleus first. Given that the distance (r) is 200 pm (or 200 × 10^-12 m) and the charge of a Li nucleus is +1 (e = 1.6 × 10^-19 C), we can substitute these values into the formula:

V_Li = (k * q_Li) / r_Li
= (9 × 10^9 N m^2/C^2 * 1.6 × 10^-19 C) / (200 × 10^-12 m)

Similarly, let's calculate the potential due to the H nucleus. Given that the distance (r) is 150 pm (or 150 × 10^-12 m) and the charge of an H nucleus is +1 (e = 1.6 × 10^-19 C), we can substitute these values into the formula:

V_H = (k * q_H) / r_H
= (9 × 10^9 N m^2/C^2 * 1.6 × 10^-19 C) / (150 × 10^-12 m)

By plugging the respective values into the formulas and performing the calculations, you should be able to determine the Coulomb potential due to the nuclei at the given point in the LiH molecule.